Evaluate - i tan-1 -3ii -12-3

(i) tan^ 1( √(3))=Θ tanΘ = √(3) tan( Θ )= tanΘ tanΘ = √(3) Θ = 60 #160; #160; or π3 (ii) ^ 1 ( 2√(3) )=Θ Θ =2√(3) ...

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Circular Measurement of Angle

Evaluate : i ...

Question

Evaluate :
i) ${tan}^{- 1} (- \sqrt{3})$
ii) ${sec}^{- 1} (\frac{2}{\sqrt{3}})$

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Solution

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