Evaluate If a + b + c = 15 and a2+b2+c2 = 125 , find ab + bc + ca
50
We use the identity (a+b+c)2 = a2+b2+c2+2ab+2bc+2ca
Given a + b + c = 15 and a2+b2+c2 = 125
Hence (15)2 = 125+2(ab+bc+ca)
225=125+2(ab+bc+ca)
225−125=2(ab+bc+ca)
100=2(ab+bc+ca)
Hence ab+bc+ca = 50