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Question

Evaluate: 230dx4+9x2

A
π6
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B
π12
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C
π24
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D
π18
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Solution

The correct option is C π24
14230dx1+94x2

Put t=32xdt=32dx or dx=23dt

=14×23[tan13x2]230

=16[tan13x2]230

=16[tan13×22×3tan10]

=16[tan11tan10]

=16[π40]=π24

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