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Question

Evaluate: 11exdx using limit of a sum.

A
e21e
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B
e22e
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C
e212e
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D
e2+1e
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Solution

The correct option is A e21e
I=1aexdx
=(1(1))limx1n(e1+e1+h+e1+2h+e1+(n1)h)
=2limn1ne1(1+eh+e2h+.....e(n1)h)
=2limn1ne((1)(eh)(n)1(eh1))
we know,
h=1(1)n=2n
2elimn1n⎜ ⎜ ⎜e2nn1e2/11⎟ ⎟ ⎟
=1elimn(e21)(2/ne2/n1)
=e21e Answer

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