Evaluate - -1 3 - x 2 -1 - dx

| x ^ 2 1|= 1 x ^ 2 1≤ x≤ 1 x ^ 2 1 1≤ x≤ 3 ⟹∫ _ 1 ^ 3 | x ^ 2 1| dx=∫ _ 1 ^ 1 (1 x ^ 2 )dx+∫ _ 1 ^ 3 (x ^ 2 1) dx #160 ...

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First Fundamental Theorem of Calculus

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Question

Evaluate $\int_{- 1}^{3} ∣ ∣ x^{2} - 1 ∣ ∣ d x$

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Solution

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