Consider the given integral.
I=∫(1−x)(2+3x)dx
I=∫(2+3x−2x−3x2)dx
I=∫(2+x−3x2)dx
I=2x+x22−3x33+C
I=2x+x22−x3+C
Hence, the value of integral is 2x+x22−x3+C.