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Question

Evaluate (1x)(2+3x)dx=

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Solution

Consider the given integral.

I=(1x)(2+3x)dx

I=(2+3x2x3x2)dx

I=(2+x3x2)dx

I=2x+x223x33+C

I=2x+x22x3+C

Hence, the value of integral is 2x+x22x3+C.


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