The correct option is A sin4−sin1−7651024
We can easily observe that at x=0 second part of integration (3x5) is undefined but it doesn’t lie in the interval of 1 to 4. Hence, we can directly integrate the whole function without breaking it.
∫40(cos(x)−3x5)dx=∫40(cos(x)−3x−5)dx
[sinx]41+[34x4]41=sin4−sin1−7651024