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Question

Evaluate 4sinxcosx2cos3x2dx

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Solution

4sinxcosx2cos3x2dx
=2sinx(2cosx2cos3x2)dx
=2sinx(cos2x+cosx)dx using 2cosAcosB=cos(A+B)+cos(AB)
=2sinxcos2xdx+2sinxcosxdx
=2sinxcos2xdx+sin2xdx
=(sin3x+sin(x))dx+sin2xdx
=sin3xdxsinxdx+sin2xdx
=cos3x3+cosxcos2x2+c
=cos3x3cos2x2+cosx+c

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