Evaluate - - 5 cos 8 x cos 2 x d x -

∫5cos 8cos2xdx=∫5×2cos 8xcos2x2dx =52∫(cos6x+cos10x)dx =52(sin 6x3+sin 10x10)+C =54(sin 6x3+sin 10x5)+C ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Trigonometric Ratios for Sum of Two Angles

Evaluate : ...

Question

Evaluate : $\int 5 cos 8 x cos 2 x d x = ?$

Open in App

Solution

$\int 5 cos 8 cos 2 x d x = \int 5 \times \frac{2 cos 8 x cos 2 x}{2} d x = \frac{5}{2} \int (cos 6 x + cos 10 x) d x = \frac{5}{2} (\frac{sin 6 x}{3} + \frac{sin 10 x}{10}) + C = \frac{5}{4} (\frac{sin 6 x}{3} + \frac{sin 10 x}{5}) + C$

Suggest Corrections

Similar questions

Evaluate : $\int \frac{x^{3}}{(x - 1) (x^{2} + 1)} d x .$

Evaluate $\int \frac{s i n x - x c o s x}{x (x + s i n x)}$ dx.

Q. Evaluate :

Evaluate : $\int_{0}^{π} \frac{x t a n x}{s e c x + t a n x} d x .$ OR Evaluate : $\int_{1}^{4} {|x-1|+|x-2|+|x-4|}dx.$

Evaluate: $\int_{0}^{\frac{π}{2}} \frac{s i n^{2} x}{s i n x + c o s x} d x .$

Evaluate: $\int_{- 1}^{2} (e^{3 x} + 7 x - 5) d x$ as a limit of sums.

$Evaluate : (i) (\frac{2}{- 3} \times \frac{5}{4}) + (\frac{5}{9} \times \frac{3}{- 10}) (i i) (2 \times \frac{1}{4}) - (\frac{- 18}{7} \times \frac{- 7}{15}) (i i i) (- 5 \times \frac{2}{15}) - (- 6 \times \frac{2}{9}) (i v) (\frac{8}{5} \times \frac{- 3}{2}) + (\frac{- 3}{10} \times \frac{9}{16})$

Join BYJU'S Learning Program

Evaluate : ∫5cos8xcos2xdx=?

∫5cos8cos2xdx=∫5×2cos8xcos2x2dx=52∫(cos6x+cos10x)dx=52(sin6x3+sin10x10)+C=54(sin6x3+sin10x5)+C

Evaluate : $\int 5 cos 8 x cos 2 x d x = ?$

$\int 5 cos 8 cos 2 x d x = \int 5 \times \frac{2 cos 8 x cos 2 x}{2} d x = \frac{5}{2} \int (cos 6 x + cos 10 x) d x = \frac{5}{2} (\frac{sin 6 x}{3} + \frac{sin 10 x}{10}) + C = \frac{5}{4} (\frac{sin 6 x}{3} + \frac{sin 10 x}{5}) + C$