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Question

Evaluate baxsinxdx

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Solution

baxsinxdx
Let u=xdu=dx
v=cosxdv=sinxdx
Integrating by parts, we get
=[xcosx]babacosxdx
=[bcosbacosa][sinx]ba
=[bcosbacosa][sinbsina]
=(bcosbsinb)(acosasina)

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