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Question

Evaluate cosxsinxcosx+sinx.(2+2sin2x)dx

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Solution

cosxsinxcosx+sinx(2+2sin2x)dx
2cosxsinxcosx+sinx(1+sin2x)dx
[sin2x+cos2x=1,sin2x=2sinxcosx]
2cosxsinxcosx+sinx(sin2x+cos2x+2sinxcosx)dx
2(cosxsinx)(cosx+sinx)dx
[(ab)(a+b)=a2b2]
2(cos2xsin2x)dx
2cos2xdx
2sinx2+C
sinx+C (Ans)

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