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Question

Evaluate cos(2x+3)dx

A
sin(2x+3)2+C
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B
sec(2x+3)2+C
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C
sin(2x+3)3+C
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D
sec(2x+3)3+C
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Solution

The correct option is A sin(2x+3)2+C
As we know that f(ax+b)dx=F(ax+b)a+C, where a,b and C are constants.
We have here,
f(x)=cos(2x+3), where a=2,b=3
So, cos(2x+3)dx=sin(2x+3)2+C

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