Question

Evaluate: $\int cose{c}^{2}xdx$

Answer 1

$t=\cot x$

$dt=-{cosec}^{2}xdx$

$-dt={cosec}^{2}xdx$

$\therefore \int {cosec}^{2}xdx=\int -dt+c$ where $c$ is the constant of integration.

$=-t+c$ where $t=\cot x$

$=-\cot x+c$