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Question

Evaluate :
cos5x+cos4x12cos3x dx

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Solution

I=cos5x+cos4x12cos3xdx

I=sin3x(cos5x+cos4x)sin3x2sin3xcos3xdx

I=(2sin3x2cos3x2)(2 cos9x2cosx2)sin3xsin6xdx

I=4sin3x2cos3x2cos9x2cosx22cos9x2sin3x2dx

I=2cos3x2cosx2 dx

I=(cos2x+cosx) dx
I=(sin2x2+sinx)+C

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