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Question

Evaluate cosx+3sinx+7cosx+sinx+1dx

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Solution

cosx+3sinx+7cosx+sinx+1dx
cosx+sinx+1cosx+sinx+1+2sinx+6cosx+sinx+1dx
=1dx+2sinx+6cosx+sinx+1dx
22u(μ+1)(μ2+1)dμ+6cosx+sinx+1dx[ μ=(tanx/2)]
4μ+12(μ2+1)dx12(μ1)dv
=4[12ln(μ2+1)+tan1μ12ln(u+1)]
2.12[ln(sec2(x2)+tan1(x2)ln(tanx2+1))]
I2=6cosx+sinx+1dx
=61μ+1dv[ μ=tan(x2)]
=6lntan(x2)+1
x+lnsec2(x2)+2tan1(x2)+tanx2+1+C


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