CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Evaluate log(1+x)(1+x)dx

Open in App
Solution

Given integral can be read as tdt for t=log(1+x)
SO answer is t22=log2(1+x)2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Special Integrals - 1
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon