Question

Evaluate :

$\int \frac{se{c}^{2}x}{tanx}dx$

Answer 1

$I=\int \frac{se{c}^{2}x}{tanx}dx$

Let $\tan x=t$

${\sec }^{2}xdx=dt$

Therefore,

$I=\int \frac{dt}{t}$

$I=\log t+C$

$I=\log \tan x+C$