Question

Evaluate: $\int \frac{sinx}{1-cosx}$

Answer 1

Formatting Area.

His waves,on correct formatting it becomes

$I=\int \frac{sinx}{1-cosx}dx$

Put $1-cosx=t$

$sinxdx=dt$

$\therefore I=\int \frac{dt}{t}$

$=log\left|t\right|+c$, where c is an arbitrary constant

$=log|1-cosx|+c$