CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
27
You visited us 27 times! Enjoying our articles? Unlock Full Access!
Question

Evaluate x2a2x dx

Open in App
Solution

put x=asecθ

dx=atanθsecθdθ

I=atanθasecθatanθsecθdθ

=a(sec2θ1)dθ

=a(tanθθ)+c

I=a[(x2a21)(sec1xa)]+c

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Integration by Substitution
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon