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Question

Evaluate
x7(1+x4)2dx

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Solution

x7dx(1+x4)2

Let u=1+x4du=4x3

=x4×x3dx(1+x4)2

=14(u1)duu2

=14uduu214duu2

=14ln|u|14(1u)+c

=14[ln1+x4+11+x4]+c

where u=1+x4

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