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Question

Evaluate: (ax2b)dxxc2x2(ax2+b)2

A
sin1(bx2acx)+k
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B
sin1(bx2+acx)+k
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C
sin1(ax2bcx)+k
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D
sin1(ax2+bcx)+k
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Solution

The correct option is D sin1(ax2+bcx)+k
I=ax2bxc2x2(ax2+b2)dx=abx2c2(ax+bx)2dx
Put ax+bx=t(abx2)dx=dt
I=dtc2t2=sin1tc=sin1(ax+bx)c

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