wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Evaluate: (ax2b)dxxc2x2(ax2+b)2

A
sin1(bx2acx)+k
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
sin1(bx2+acx)+k
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
sin1(ax2bcx)+k
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
sin1(ax2+bcx)+k
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D sin1(ax2+bcx)+k
I=ax2bxc2x2(ax2+b2)dx=abx2c2(ax+bx)2dx
Put ax+bx=t(abx2)dx=dt
I=dtc2t2=sin1tc=sin1(ax+bx)c

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Integration of Irrational Algebraic Fractions - 2
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon