1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Mathematics
Special Integrals - 1
Evaluate : ...
Question
Evaluate :
∫
e
sin
−
1
x
(
ℓ
n
x
√
1
−
x
2
+
1
x
)
d
x
Open in App
Solution
∫
e
sin
−
1
x
(
ln
x
√
1
−
x
2
+
1
x
)
d
x
=
∫
e
sin
−
1
x
ln
x
d
(
sin
−
1
x
)
+
∫
e
sin
−
1
x
d
x
x
=
e
sin
−
1
x
ln
x
−
∫
e
sin
−
1
x
x
d
x
+
∫
e
sin
−
1
x
x
d
x
=
e
sin
−
1
x
ln
x
+
c
Suggest Corrections
0
Similar questions
Q.
Derivatie of
e
s
i
n
−
1
x
w
.
r
.
t
.
s
i
n
−
1
i
s