Evaluate -ex 1x - 1x2 dx

The correct option is C e^xx+C ∫e^x( 1x 1x^2)d x ∫( e^xx e^xx^2)dx ∫e^xxdx ∫e^xx^2dx ∫e^xxdx + e^xx + ∫ e^xxdx =e^xx + c ...

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Special Integrals - 1

Evaluate ∫e...

Question

Evaluate $\int e^{x} (\frac{1}{x} - \frac{1}{x^{2}}) d x$

\frac{e^{x}}{x^{2}} + C

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- \frac{e^{x}}{x^{2}} + C

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\frac{e^{x}}{x} + C

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- \frac{e^{x}}{x} + C

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\int e^{x} {(\frac{1 - x}{1 + x^{2}})}^{2} d x is equal to (a) \frac{e^{x}}{1 + x} + C (b) - \frac{e^{x}}{1 + x^{2}} + C (c) \frac{e^{x}}{(1 + x}

$\int \frac{x e^{x}}{(1 + x)^{2}} d x =$

$\int e^{x} {(\frac{1 - x}{1 + x^{2}})}^{2}$ dx

l n = \int (1 + x + x^{- 1}) e^{x + x^{- 1}} d x =

\int \frac{e^{x} (2 - x^{2})}{(1 - x) \sqrt{1 - x^{2}}} d x

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