Question

Evaluate: $\int \frac{e^{2x}}{1+e^x}dx$

Answer 1

$l=(1-e^x)-log|e^x+1|+c$

$=(t-logt)+c$

$=(e^x+1)-log(e^x+1)+c$

$=e^x-log(e^x+1)+1+c$

$=e^x-log(e^x+1)+c$