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Question

Evaluate: (3x2)2x2x+1dx

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Solution

=(3x2)2x2x+1dx

=3(x23)2x2x+1dx

=34(4x153)2x2x+1dx

=34[(4x1)2x2x+1dx532x2x+1dx]

=34(4x1)2x2x+1dx542x2x+1dx

=34(2x2x+1)54×2x2x2+12dx

=34(2x2x+1)522x22×x×14+116+12116dx

=34(2x2x+1)522 (x14)(74)2dx

=34(2x2x+1)522[12×(x14)x2x2+12+12×716×sin1(4x17)]+C

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