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Byju's Answer
Standard XII
Physics
Antiderivative
Evaluate x+1/...
Question
Evaluate
∫
(
x
+
1
x
)
2
d
x
A
x
3
3
−
1
x
+
x
+
c
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B
x
3
3
+
1
x
+
2
x
+
c
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C
x
3
3
−
1
x
+
2
x
+
c
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D
x
3
3
+
1
x
+
x
+
c
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Solution
The correct option is
C
x
3
3
−
1
x
+
2
x
+
c
Given function is
f
(
x
)
=
(
x
+
1
x
)
2
⇒
f
(
x
)
=
x
2
+
1
x
2
+
2
=
x
2
+
x
−
2
+
2
So,
∫
(
x
+
1
x
)
2
d
x
=
∫
(
x
2
+
x
−
2
+
2
)
d
x
⇒
∫
x
2
d
x
+
∫
x
−
2
d
x
+
∫
2
d
x
⇒
x
3
3
−
1
x
+
2
x
+
c
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