Question

Evaluate:-
$\underset{0}{\overset{1}{\int }}\left(4+x^2\right)dx$

Answer 1

${\int }_0^1(4+x^2)dx$

$={[4x+\frac{x^3}{3}]}_0^1$

$=4(1-0)+\frac{1}{3}(1-0)$

$=4+\frac{1}{3}=\frac{12+1}{3}=\frac{13}{3}$