Evaluate- -0-x-a2cos2x - b2sin2xdx

The correct option is A π^22ab Use both (a+b x) and (2a x) properties. ...

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Property 1

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Question

Evaluate: $π \int 0 \frac{x}{a^{2} {cos}^{2} x + b^{2} {sin}^{2} x} d x$

\frac{π^{2}}{a b}

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\frac{π^{2}}{2 a b}

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\frac{2 π^{2}}{a b}

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\frac{π^{2}}{4 a b}

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Solution

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Similar questions

f (x) = \int_{0}^{1} t sin (x + π t) d t, x \in R

f (x) = 1 \int 0 t sin (x + π t) d t, x \in R

y = \sqrt{4 - x^{2}}, y \geq \sqrt{2} s i n (\frac{x π}{2 \sqrt{2}})

y = \sqrt{\frac{1 - cos 2 x}{1 + cos 2 x}}, x \in (0, \frac{π}{2}) \cup (\frac{π}{2}, π)

\frac{d y}{d x}

{lim}_{x \to \frac{π}{2}} \frac{tan 2 x}{x - \frac{π}{2}}

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