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Question

Evaluate 44|x+2| dx

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Solution

f(x)=|x+2|
={x+2 ,x2(x+2) ,x<2

So,
44|x+2|dx=24(x+2)dx+42(x+2)dx
=[x222x]24+[x22+2x]42
=2+4(8+8)+8+8(24)
=20

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