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Question

Evaluate: 20x[x]dx.

A
53
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B
83
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C
32
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D
23
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Solution

The correct option is C 32
We have,
I=20x [x] dx

Since,
[x]=0,when 0<x<1
[x]=1,when 1<x<2

Therefore
I=100 dx+21x dx

I=0+[x22]21

I=12(2212)

I=12(41)

I=32

Hence, Option C is the answer.

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