Question

Evaluate: ${\int }_0^{\pi }(cosx+x^2)dx$

• A. $\frac{{\pi }^3}{3}-1$
• B. $\frac{{\pi }^3}{3}$
• C. $\frac{{\pi }^3}{3}+1$
• D. \N

Answer 1

The correct option is B $\frac{{\pi }^3}{3}$

${\int }_0^{\pi }(cosx+x^2)dx$
$={\int }_0^{\pi }cosxdx+{\int }_0^{\pi }{x}^{2}dx$
$=sinx{|{}_0^{\pi }+\frac{x^3}{3}|}_0^{\pi }=(0-0)+(\frac{{\pi }^3}{3}-0)=\frac{{\pi }^3}{3}$