wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Evaluate: (sin1x)2dx

Open in App
Solution

Solution : -
I=(sin1x)2dx

I=sin1x.sin1xdx

Put sin1x=t ___(1)

sint=x ____(2)

costdt=dx ____(3)

I=t2costdt

I=t2costdt2tsintdt

=t2sint2[t.sintdt]

=t2sint2[tcost+costdt]

=t2sint+2tcost2sint+c

=(sin1x)2x+2sin1x1x22x+c

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon