Question

Evaluate:

$\int {\sin }^{2}x{\cos }^{2}xdx$

Answer 1

$u=sin2x,du=2cos2xdx$

$\frac{1}{2}\int udu=\frac{1}{4}{u}^2+C$

$\frac{1}{4}{sin}^{2}2x+C$