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Question

Evaluate sin3xsin2xdx.

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Solution

sin3xsin2xdx
=sin3x2sinxcosxdx
I=2sin4xcosxdx

Let t=sinxdt=cosxdx

I=2t4dt

=2(t55)+c , where c is the constant of integration

=2sin5x5+c , where t=sinx

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