Question

Evaluate:

$\int \sin x.{\cot }^{3}x.dx$

Answer 1

$\int sinx.co{t}^{3}x.dx=\int \left(co{s}^{3}x/si{n}^{2}x\right).dx=\int cosx(1-si{n}^{2}x).dx/si{n}^{2}x$

$=\int (cosx/si{n}^{2}x-cosx).dx=-1/sinx-sinx+c$