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Byju's Answer
Standard XII
Mathematics
Logarithmic Differentiation
Evaluate: ∫√5...
Question
Evaluate:
∫
√
5
−
2
x
+
x
2
d
x
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Solution
∫
√
5
−
2
x
+
x
2
d
x
=
∫
√
x
2
−
2
x
+
1
+
4
d
x
=
∫
√
(
x
−
1
)
2
+
2
2
d
x
=
x
−
1
2
√
x
2
−
2
x
+
5
+
2
log
∣
∣
(
x
−
1
)
+
√
x
2
−
2
x
+
5
+
c
∣
∣
(
∵
∫
√
x
2
+
a
2
d
x
=
x
2
√
x
2
+
a
2
+
a
2
2
log
∣
∣
x
+
√
x
2
+
a
2
∣
∣
)
Where
c
is constant of integration.
Hence, the required integration is
x
−
1
2
√
x
2
−
2
x
+
5
+
2
log
∣
∣
(
x
−
1
)
+
√
x
2
−
2
x
+
5
+
c
∣
∣
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Standard XII Mathematics
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