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Question

Evaluate: 52x+x2dx

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Solution

52x+x2dx
=x22x+1+4dx
=(x1)2+22dx
=x12x22x+5+2log(x1)+x22x+5+c

(x2+a2dx=x2x2+a2+a22logx+x2+a2)

Where c is constant of integration.
Hence, the required integration is x12x22x+5+2log(x1)+x22x+5+c

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