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Question

Evaluate :

1cos2x1+cos2xdx

A
log(secx)+C
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B
log(tanx)+C
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C
log(cosx)+C
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D
log(sinx)+C
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Solution

The correct option is A log(secx)+C
I=1cos2x1+cos2xdx

I=2sin2x2cos2xdx

I=tanx dx
I=log(secx)+C

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