wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Evaluate (x3ex+cosx)dx

A
x44ex+sinx
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3x2ex+sinx
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x44exsinx
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
3x2exsinx
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C x44exsinx
(x3ex+cosx)dx
=x3dxexdx+cosx dx
=x44exsinx

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Integration
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon