Evaluate:

$(i v)$ $(0.2)^{3} - (0.3)^{3} + (0.1)^{3}$

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Solution

Given,

$(0.2)^{3} - (0.3)^{3} + (0.1)^{3}$

Let $a = 0.2, b = - 0.3$ and $c = 0.1$

$∴ a + b + c = 0.2 - 0.3 + 0.1 = 0.$

$∴ a^{3} + b^{3} + c^{3} = 3 a b c$

$(0.2)^{3} + (- 0.3)^{3} + (0.1)^{3} = 3 \times 0.2 \times (- 0.3) \times (0.1)$

$= - 0.018$

$(0.2)^{3} - (0.3)^{3} + (0.1)^{3} = - 0.018$

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