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Shivaji escapes

Evaluate:iv 9...

Question

Evaluate:
(iv) $(9 a - 3 a) + 4 a$ .

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Solution

$(9 a - 3 a) + 4 a = 6 a + 4 a$

[On removing the small brackets ]

$= 10 a$

Hence, $(9 a - 3 a) + 4 a = 10 a$ .

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Solve the following

(a) $p + 4 = 15$

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(c) $x + 2 x + 1 = 4 x + 6$

(d) $9 a - 3 a - 4 a - 6 = 0$

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Q. State True or False.

3 a^{2} (2 a^{2} - 3) + 4 a (4 a^{3} + 3) - 12 (a + 1)

= 14 a^{4} - 9 a^{2} - 12

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