Question

Evaluate $K_p$ for the reaction $:H_2+I_2\rightleftharpoons 2HI$. If $2$ moles each of $H_2$ and $I_2$ are taken initially. The equilibrium moles of $HI$ is $2$.

• A. $2.5$
• B. $2$
• C. $0.25$
• D. $1.0$

Answer 1

The correct option is B $2$

$H_2+I_2=2HI$
$2$ $2$ $0$
$\frac{2-1}{1}$ + $\frac{2-1}{1}=\frac{2}{2}$
$K_p=\left(K_c\right)(RT{)}^{{\Delta }_{n_g}}$ (here $\Delta n_g=0$)
$K_p=K_c=2$
$=2$