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Byju's Answer
Standard IX
Mathematics
Comparison of Quantities Using Exponents
Evaluate: 10...
Question
Evaluate:
(
103
)
3
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Solution
According to the equation,
(
a
+
b
)
3
=
a
3
+
b
3
+
3
a
b
(
a
+
b
)
we get,
(
103
)
3
=
(
100
+
3
)
3
By using the formula,
=
100
3
+
3
3
+
3
(
100
)
(
3
)
(
100
+
3
)
=
1000000
+
27
+
900
(
103
)
On further calculation,
=
1000000
+
27
+
92700
(
103
)
3
=
1092727
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10
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103
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(
103
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Comparison of Quantities Using Exponents
Standard IX Mathematics
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