Evaluate
$(2 p + 3) (2 p - 3) (4 p^{2} + 9)$

Open in App

Solution

$(2 p + 3) (2 p - 3) (4 p^{2} + 9)$
Using $(a - b) (a + b) = a^{2} - b^{2}$
$= (4 p^{2} - 9) (4 p^{2} + 9)$
$= 16 p^{4} - 81$

Suggest Corrections

Similar questions

Find the continued products:
(i) $(x + 1) (x - 1) (x^{2} + 1)$
(ii) $(x - 3) (x + 3) (x^{2} + 9)$
(iii) $(3 x - 2 y) (3 x + 2 y) (9 x^{2} + 4 y^{2})$
(iv) $(2 p + 3) (2 p - 3) (4 p^{2} + 9)$

Q. Simplify:

(P + \frac{P}{3}) (2 P + \frac{P}{2}) (3 P - \frac{2 P}{3})

Q. Mark (✓) against the correct answer:
10p² + 11p + 3 = ?
(a) (2p + 3)(5p + 1)
(b) (5p + 3)(2p + 1)
(c) (5p − 3)(2p − 1)
(d) none of these

Q. For what value of 'p' the pair of linear equations

(p + 2) x - (2 p + 1) y = 3 (2 p - 1)

and

2 x - 3 y = 7

will be have a unique solution.

Q. Evaluate:

(8 p^{3} - 4 p^{2}) \div 2 p^{2}

Join BYJU'S Learning Program

Evaluate(2p+3)(2p−3)(4p2+9)

(2p+3)(2p−3)(4p2+9)Using (a−b)(a+b)=a2−b2=(4p2−9)(4p2+9)=16p4−81

Evaluate
$(2 p + 3) (2 p - 3) (4 p^{2} + 9)$

$(2 p + 3) (2 p - 3) (4 p^{2} + 9)$
Using $(a - b) (a + b) = a^{2} - b^{2}$
$= (4 p^{2} - 9) (4 p^{2} + 9)$
$= 16 p^{4} - 81$