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Byju's Answer
Standard X
Mathematics
Range of Trigonometric Ratios from 0 to 90 Degrees
Evaluate : ...
Question
Evaluate :
(
3
−
cot
30
∘
)
−
tan
3
60
∘
+
2
tan
60
∘
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Solution
We know that
cot
30
∘
=
√
3
,
tan
60
∘
=
√
3
3
−
cot
30
∘
−
tan
3
60
∘
+
2
tan
60
∘
=
3
−
√
3
−
(
√
3
)
3
+
2
√
3
=
3
−
√
3
−
3
√
3
+
2
√
3
=
3
−
2
√
3
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Q.
Question 5
(
√
3
+
1
)
(
3
−
c
o
t
30
∘
)
=
t
a
n
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60
∘
−
2
s
i
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60
∘
Q.
Prove the following:
(
√
3
+
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)
(
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−
cot
30
∘
)
=
tan
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∘
−
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sin
60
∘
Q.
Evaluate:
∫
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d
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Q.
Evaluate:
2
sin
2
30
o
cot
30
o
−
3
cos
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60
o
sec
2
30
o
.
Q.
Evaluate the following:
2
s
i
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∘
+
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c
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∘
–
3
t
a
n
45
∘
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Standard X Mathematics
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