Evaluate : (3a−12)(3a−12)
(a−b)2=a2−2ab+b2 (3a−12)(3a−12) =(3a−12)2 =(3a)2−2×3a×12+(12)2 =9a2−3a+14
Find the value of : (3a−12)(3a−12)
Factorise:
9a2+19a2−2−12a+43a