Evaluate (53)−2×(53)−14
Given, (53)−2×(53)−14
Using law of exponents, am×an=(a)m+n,
(53)−2×(53)−14 =(53)−2−14 =(53)−16
Using coafactors of the elements of second row, evaluate Δ=∣∣ ∣∣538201123∣∣ ∣∣
(2/5)*(-3/7)-1/6*3/2+1/14*2/5