Evaluate -764 13-27 13 3- 14

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Byju's Answer

Standard VI

Mathematics

Addition of Fractions

Evaluate [76...

Question

Evaluate
${⎡ ⎢ ⎣ 7 (64^{\frac{1}{3}} + 27^{\frac{1}{3}})^{3} ⎤ ⎥ ⎦}^{\frac{1}{4}}$

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Solution

$[7 (64^{1 / 3} + 27^{1 / 3})^{3}]^{1 / 4} = [7 (4 + 3)^{3}]^{1 / 4} = [7^{4}]^{1 / 4} = 7$

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Similar questions

{(7 {(64^{1 / 3} + 27^{1 / 3})}^{3})}^{1 / 4}

Q. Evaluate:

{[5 {(8^{\frac{1}{3}} + 27^{\frac{1}{3}})}^{3}]}^{\frac{1}{4}}

Evaluate (i) $(1^{3} + 2^{3} + 3^{3})^{\frac{1}{2}}$ (ii) ${[5 {(8^{\frac{1}{3}} + 27^{\frac{1}{3}})}^{3}]}^{\frac{1}{4}}$ (iii) $\frac{2^{0} + 7^{0}}{5^{0}}$ (iv) ${[(16)^{\frac{1}{2}}]}^{\frac{1}{2}}$

Q. Simplify :

{[5 {(8^{\frac{1}{3}} + 27^{\frac{1}{3}})}^{3}]}^{\frac{1}{4}}

Q. Fill in the blanks

{(\begin{matrix} 5 (8^{1 / 3} + 27^{1 / 3})^{3} \end{matrix})}^{1 / 4} =

_____.

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Evaluate⎡⎢⎣7(6413+2713)3⎤⎥⎦14

[7(641/3+271/3)3]1/4=[7(4+3)3]1/4=[74]1/4=7

Evaluate
${⎡ ⎢ ⎣ 7 (64^{\frac{1}{3}} + 27^{\frac{1}{3}})^{3} ⎤ ⎥ ⎦}^{\frac{1}{4}}$

$[7 (64^{1 / 3} + 27^{1 / 3})^{3}]^{1 / 4} = [7 (4 + 3)^{3}]^{1 / 4} = [7^{4}]^{1 / 4} = 7$