Question

Evaluate:

${\left(\frac{1}{2}\right)}^{-2}-{\left(\frac{1}{2}\right)}^{-2}÷{\left(\frac{1}{4}\right)}^{-2}$

Answer 1

Solution:-

we have ${\left(\frac{1}{2}\right)}^{-2}-{\left(\frac{1}{2}\right)}^{-2}÷{\left(\frac{1}{4}\right)}^{-2}$

$\Rightarrow \left(\frac{1}{2^2}\right)-{\left(\frac{1/2}{1/4}\right)}^{-2}$ Applying BODAMAS Rule

$\Rightarrow {\left(\frac{1}{2}\right)}^{-2}-(2{)}^{-2}$

$\Rightarrow \frac{1}{2^{-2}}-\frac{1}{2^2}$

$\Rightarrow 4-\frac{1}{4}\Rightarrow \frac{15}{4}$