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Byju's Answer
Standard VI
Mathematics
Addition of Fractions
Evaluate [ ...
Question
Evaluate
[
5
4
+
−
1
2
]
+
−
3
2
−
5
4
+
(
1
2
+
−
3
2
)
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Solution
[
5
4
+
−
1
2
]
+
−
3
2
−
5
4
+
(
1
2
+
−
3
2
)
=
[
5
+
(
−
2
)
4
]
+
(
−
3
)
×
(
−
5
)
8
+
(
1
+
(
−
3
)
2
)
=
3
4
+
15
8
+
−
2
2
=
3
4
+
15
8
−
1
=
6
+
15
−
8
8
=
1
8
Hence the required answer is
1
8
.
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0
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