Evaluate (53)−2×(53)−14
(35)−16
(35)16
(53)16
(53)−16
Given, (53)−2×(53)−14
Using law of exponents, am×an=(a)m+n
⇒(53)−2−14 ⇒(53)−16 ⇒(35)16
Using coafactors of the elements of second row, evaluate Δ=∣∣ ∣∣538201123∣∣ ∣∣
(2/5)*(-3/7)-1/6*3/2+1/14*2/5